Int 21/AH=36h

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DOS 2+ - GET FREE DISK SPACE

AH = 36h
DL = drive number (00h = default, 01h = A:, etc)

Return:
AX = FFFFh if invalid drive else AX = sectors per cluster BX = number of free clusters CX = bytes per sector DX = total clusters on drive

Notes: Free space on drive in bytes is AX * BX * CX. Total space on drive in bytes is AX * CX * DX. "lost clusters" are considered to be in use. According to Dave Williams' MS-DOS reference, the value in DX is incorrect for non-default drives after ASSIGN is run. This function does not return proper results on CD-ROMs; use AX=4402h"CD-ROM" instead. (FAT32 drive) the reported total and free space are limited to 2G-32K should they exceed that value

See Also: AH=1Bh - AH=1Ch - AX=4402h"CD-ROM" - AX=7303h Category: DOS Kernel - Int 21h - D

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